DETERMINING BATMAN'S VELOCITY
By: Alex Smith and Marianne Grima
We analyzed a scene from Batman Begins. Batman is attempting to stop a moving car three stories beneath him in a parking structure. As the car is driving down the ramp, Batman falls and aims to hit the vehicle as it passes under him. In the scene. He begins with an initial velocity of zero and accelerates at 9.8m/s/s due to gravity. When we froze the scene to count the levels in the parking structure, there were three levels, which is approximately 30 feet or 9 meters. At ten feet a story, or thirty feet, falling with a mass of around 190 pounds, Batman's velocity would amount to 13.622 m/s.
Equations:
Vi = 0 m/s
a = 9.8 m/s/s
mass = 190 lb. or 86.18 kg
d = 30 feet of 9 meters
T = sqrt(d/.5a)
T = sqrt{9/.5(9.8)}
T = 1.39s
Vf = Vi + a(t)
Vf = 13.622 m/s |